Question

#4 let $f(x) = 5 - 2x$. what is $f(1)$? a. 1 b. 3 c. 5 d. 7 #5 let $p(x) = x^2 - 4$. what is $p(0)$? a. -4 b. -2 c. 0 d. 4

Explanation:

For #4:

Step1: Substitute $x=1$

$f(1) = 5 - 2(1)$

Step2: Calculate the result

$f(1) = 5 - 2 = 3$

For #5:

Step1: Substitute $x=0$

$p(0) = 0^2 - 4$

Step2: Calculate the result

$p(0) = 0 - 4 = -4$

Answer:

#4: B. 3
#5: A. -4