Question

a line has a slope of -1 and passes through the point (-12, 11). write its equation in slope - intercept form. write your answer using integers, proper fractions, and improper fractions in simplest form.

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $m$ is the slope and $(x_1,y_1)$ is a point on the line. We know that $m=- 1$ and $(x_1,y_1)=(-12,11)$. Substitute these values into the point - slope form:
$y - 11=-1(x - (-12))$
Simplify the right - hand side: $y - 11=-1(x + 12)$

Step2: Convert to slope - intercept form

The slope - intercept form is $y=mx + b$. Expand the right - hand side of the equation from Step 1:
$y-11=-x - 12$
Then, add 11 to both sides of the equation to solve for $y$:
$y=-x-12 + 11$
Simplify the constants: $y=-x-1$

Answer:

$y=-x - 1$