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the longest side of a triangle similar to $\triangle xyz$ is 39 units long. find the other side lengths of the triangle.
the other side lengths are $\boldsymbol{square}$ units and $\boldsymbol{square}$ units.
(note: the side lengths of $\triangle xyz$ are $xy=13$, $yz=12$, $xz=10$)
Step1: Find similarity ratio
First, identify the longest side of $\triangle XYZ$: it is $XY = 13$. The longest side of the similar triangle is 39. Calculate the ratio:
$\text{Ratio} = \frac{39}{13} = 3$
Step2: Calculate side 1 (corr to XZ)
Multiply the length of $XZ=10$ by the ratio:
$10 \times 3 = 30$
Step3: Calculate side 2 (corr to YZ)
Multiply the length of $YZ=12$ by the ratio:
$12 \times 3 = 36$
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The other side lengths are 30 units and 36 units.