Question

long division whole number divided by whole number 2 1 \longdiv{6 1 8}

Explanation:

Step1: Divide the first two digits

We look at how many times 21 can go into 61. Since \(21\times2 = 42\) and \(21\times3=63\) (which is too big), we use 2. Subtract \(21\times2 = 42\) from 61: \(61 - 42=19\).

Step2: Bring down the next digit

Bring down the 8 to make the number 198.

Step3: Divide the new number

Now, we find how many times 21 goes into 198. \(21\times9 = 189\), subtract \(189\) from \(198\): \(198 - 189 = 9\).

Step4: Combine the results

The quotient from the first part is 2 (in the tens place), the quotient from the second part is 9 (in the ones place), and the remainder is 9. So, \(618\div21 = 29\frac{9}{21}=29\frac{3}{7}\approx29.43\) (if we want a decimal), but as a whole - number division with remainder, it's \(29\) with a remainder of \(9\). If we are doing long - division to get a decimal, we can continue by adding a decimal point and zeros to 618 (making it 618.000...) and keep dividing. But for the long - division of whole numbers (with remainder), the result is quotient 29 and remainder 9.

Answer:

When performing \(618\div21\) using long division:

• The quotient is \(29\) and the remainder is \(9\) (or as a decimal, approximately \(29.43\)).