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the longer leg of a right triangle is 17 cm longer than the length of t…

Question

the longer leg of a right triangle is 17 cm longer than the length of the shorter leg x. the hypotenuse is 25 cm. part: 0 / 4 part 1 of 4 (a) write an equation in terms of x that represents the given relationship. the equation is

Explanation:

Step1: Define sides

Shorter leg = $x$, longer leg = $x + 17$, hypotenuse = $25$.

Step2: Apply Pythagorean theorem

$x^{2}+(x + 17)^{2}=25^{2}$.

Answer:

$x^{2}+(x + 17)^{2}=625$