Question

1. $(2x^2 + 3y^2 + 4) - (4x^2 + 4y^2 - 5)$
2. $(3x + 5y + 10) - (-4x + 2y^2 + 5)$

Explanation:

Step1: Distribute the negative sign

$(2x^2 + 3y + 4) - 4x^2 - 4y + 5$

Step2: Combine like $x^2$ terms

$2x^2 - 4x^2 = -2x^2$

Step3: Combine like $y$ terms

$3y - 4y = -y$

Step4: Combine constant terms

$4 + 5 = 9$

Step5: Distribute the negative sign

$(3x + 5y + 10) + 4x - 2y^2 - 5$

Step6: Combine like $x$ terms

$3x + 4x = 7x$

Step7: Combine constant terms

$10 - 5 = 5$

Answer:

1. $-2x^2 - y + 9$
2. $7x + 5y - 2y^2 + 5$