Question

1. $3xy^{8} \cdot 2x^{-1}y^{-8}$

Explanation:

Step1: Group constant and like terms

$(3 \cdot 2) \cdot (x \cdot x^{-1}) \cdot (y^8 \cdot y^{-8})$

Step2: Multiply constants and apply exponent rules

$6 \cdot x^{1+(-1)} \cdot y^{8+(-8)}$

Step3: Simplify exponents

$6 \cdot x^{0} \cdot y^{0}$

Step4: Evaluate zero exponents ($a^0=1$)

$6 \cdot 1 \cdot 1$

Answer:

$6$