Question

1. $(4x^{-4}y^{2})^{3}$

Explanation:

Step1: Apply power to constant term

$4^3 = 64$

Step2: Apply exponent rule to $x$-term

$(x^{-4})^3 = x^{-4 \times 3} = x^{-12}$

Step3: Apply exponent rule to $y$-term

$(y^2)^3 = y^{2 \times 3} = y^6$

Step4: Combine all simplified terms

$64 \times x^{-12} \times y^6 = \frac{64y^6}{x^{12}}$

Answer:

$\frac{64y^6}{x^{12}}$