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Question
- \\(\frac{5}{17} = \frac{19}{x + 4}\\)
Step1: Cross - multiply the equation
Given the equation $\frac{5}{17}=\frac{19}{x + 4}$, by the cross - multiplication property of proportions (if $\frac{a}{b}=\frac{c}{d}$, then $a\times d=b\times c$), we get $5\times(x + 4)=17\times19$.
Step2: Expand the left - hand side and calculate the right - hand side
Expand the left - hand side: $5x+20$. Calculate the right - hand side: $17\times19 = 323$. So the equation becomes $5x+20 = 323$.
Step3: Isolate the term with $x$
Subtract 20 from both sides of the equation: $5x=323 - 20$. Calculate $323-20 = 303$, so $5x = 303$.
Step4: Solve for $x$
Divide both sides of the equation by 5: $x=\frac{303}{5}=60.6$.
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$x = \frac{303}{5}$ (or $x = 60.6$)