Question

17.) a=2, b=2√3, c=???

Explanation:

Assuming this is a right - triangle problem where \(c\) is the hypotenuse and we use the Pythagorean theorem \(c^{2}=a^{2}+b^{2}\).

Step 1: Substitute the values of \(a\) and \(b\) into the formula

Given \(a = 2\) and \(b=2\sqrt{3}\), we substitute these values into \(c^{2}=a^{2}+b^{2}\).
So \(a^{2}=2^{2} = 4\) and \(b^{2}=(2\sqrt{3})^{2}=2^{2}\times(\sqrt{3})^{2}=4\times3 = 12\).

Step 2: Calculate \(c^{2}\)

\(c^{2}=a^{2}+b^{2}=4 + 12=16\)

Step 3: Solve for \(c\)

Take the square root of both sides. Since \(c\) represents the length of a side of a triangle, we take the positive square root. So \(c=\sqrt{16} = 4\)

Answer:

\(c = 4\)