Question

1. \\(- 3x - 4 = 23\\)\

\\(x = \square\\)\

1. \\(3 - 2x = 17\\)\

\\(x = \square\\)\

1. \\(\frac{x - 16}{4} = 12\\)\

\\(x = \square\\)\

1. \\(\frac{1}{2}x + 3 = 9\\)\

\\(x = \square\\)

Explanation:

Problem 2: $-3x - 4 = 23$

Step1: Add 4 to both sides

$-3x - 4 + 4 = 23 + 4$
$-3x = 27$

Step2: Divide by -3

$\frac{-3x}{-3} = \frac{27}{-3}$
$x = -9$

Step1: Subtract 3

$3 - 2x - 3 = 17 - 3$
$-2x = 14$

Step2: Divide by -2

$\frac{-2x}{-2} = \frac{14}{-2}$
$x = -7$

Step1: Multiply by 4

$4 \times \frac{x - 16}{4} = 12 \times 4$
$x - 16 = 48$

Step2: Add 16

$x - 16 + 16 = 48 + 16$
$x = 64$

Answer:

$x = -9$

Problem 6: $3 - 2x = 17$