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Question
- divide \\(\sqrt{\frac{72}{4}}\\). \\(\bigcirc\\ 2\sqrt{3}\\) \\(\bigcirc\\ 6\sqrt{2}\\) \\(\bigcirc\\ 3\sqrt{2}\\) \\(\bigcirc\\ 6\sqrt{3}\\)
Step1: Simplify the fraction inside the square root
First, we simplify the fraction \(\frac{72}{4}\). Dividing 72 by 4 gives us 18. So now we have \(\sqrt{18}\).
Step2: Simplify the square root
We can factor 18 into \(9\times2\), so \(\sqrt{18}=\sqrt{9\times2}\). Using the property of square roots \(\sqrt{ab}=\sqrt{a}\times\sqrt{b}\) (where \(a = 9\) and \(b = 2\)), we get \(\sqrt{9}\times\sqrt{2}\). Since \(\sqrt{9}=3\), this simplifies to \(3\sqrt{2}\).
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\(3\sqrt{2}\) (corresponding to the option with \(3\sqrt{2}\))