Question

$(2c + 1)^2$

Explanation:

Step1: Apply square of sum formula

Recall the formula $(a+b)^2 = a^2 + 2ab + b^2$, where $a=2c$, $b=1$.

Step2: Calculate each term

$a^2=(2c)^2=4c^2$, $2ab=2*(2c)*1=4c$, $b^2=1^2=1$.

Step3: Combine the terms

Add the calculated terms together.

Answer:

$4c^2 + 4c + 1$