Question

1. $2x + 8 = 16$
2. $\frac{j}{3} + 5 = 9$

Explanation:

Step1: Isolate term with $x$

Subtract 8 from both sides:
$2x + 8 - 8 = 16 - 8$
$2x = 8$

Step2: Solve for $x$

Divide both sides by 2:
$\frac{2x}{2} = \frac{8}{2}$
$x = 4$

Step3: Isolate term with $j$

Subtract 5 from both sides:
$\frac{j}{3} + 5 - 5 = 9 - 5$
$\frac{j}{3} = 4$

Step4: Solve for $j$

Multiply both sides by 3:
$\frac{j}{3} \times 3 = 4 \times 3$
$j = 12$

Answer:

For $2x + 8 = 16$: $x = 4$
For $\frac{j}{3} + 5 = 9$: $j = 12$