4(x - 1) = \\frac{1}{2}(x - 8)

$4(x - 1) = \\frac{1}{2}(x - 8)$

4(x - 1) = \frac{1}{2}(x - 8)

Multiply both sides by 2 to cancel the denominator:
$$2 \times 4(x-1) = 2 \times \frac{1}{2}(x-8)$$
$$8(x-1) = x-8$$

Distribute the 8 across the parentheses:
$$8x - 8 = x - 8$$

Subtract $x$ from both sides:
$$8x - x - 8 = -8$$
$$7x - 8 = -8$$

Add 8 to both sides:
$$7x = -8 + 8$$
$$7x = 0$$

Divide both sides by 7:
$$x = \frac{0}{7}$$

$x = 0$