Question

1. $12x^2 - 147 = 0$

Explanation:

Step1: Isolate the $x^2$ term

$12x^2 = 147$

Step2: Solve for $x^2$

$x^2 = \frac{147}{12} = \frac{49}{4}$

Step3: Take square root of both sides

$x = \pm\sqrt{\frac{49}{4}}$

Step4: Simplify the square root

$x = \pm\frac{7}{2}$

Answer:

$x = \frac{7}{2}$ or $x = -\frac{7}{2}$