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Question
- $(sqrt5{8})^4$
Step1: Rewrite root as exponent
$\sqrt[5]{8} = 8^{\frac{1}{5}}$
Step2: Apply exponent power rule
$(8^{\frac{1}{5}})^4 = 8^{\frac{4}{5}}$
Step3: Rewrite 8 as power of 2
$8 = 2^3$, so $8^{\frac{4}{5}} = (2^3)^{\frac{4}{5}}$
Step4: Simplify the exponent
$(2^3)^{\frac{4}{5}} = 2^{\frac{12}{5}}$
Step5: Optional: Rewrite as mixed radical
$2^{\frac{12}{5}} = 2^{2+\frac{2}{5}} = 2^2 \times 2^{\frac{2}{5}} = 4\sqrt[5]{4}$
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$2^{\frac{12}{5}}$ or $4\sqrt[5]{4}$