Question

$\

$$\begin{cases} y=7 \\\\ x=3y-4 \\end{cases}$$

$
$\

$$\begin{cases} y=\\frac{3}{2}x+7 \\\\ x=-4 \\end{cases}$$

$

Explanation:

Step1: Substitute y=7 into x's equation

Substitute $y=7$ into $x=3y-4$:
$x=3\times7 - 4$

Step2: Calculate x's value

$x=21-4=17$

Step3: Substitute x=-4 into y's equation

Substitute $x=-4$ into $y=\frac{3}{2}x + 7$:
$y=\frac{3}{2}\times(-4)+7$

Step4: Calculate y's value

$y=-6 + 7=1$

Answer:

For the first system: $x=17$, $y=7$
For the second system: $x=-4$, $y=1$