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$\\frac{16}{120}=\\frac{j}{15}$ $90 = 10x - 8$

Question

$\frac{16}{120}=\frac{j}{15}$
$90 = 10x - 8$

Explanation:

Step1: Solve for $j$ (cross-multiply)

$16 \times 15 = 120j$

Step2: Calculate left-hand side

$240 = 120j$

Step3: Isolate $j$ (divide by 120)

$j = \frac{240}{120}$

Step4: Solve for $x$ (add 8 to both sides)

$90 + 8 = 10x$

Step5: Calculate left-hand side

$98 = 10x$

Step6: Isolate $x$ (divide by 10)

$x = \frac{98}{10}$

Answer:

$j = 2$, $x = 9.8$