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Question
$\frac{16}{120}=\frac{j}{15}$
$90 = 10x - 8$
Step1: Solve for $j$ (cross-multiply)
$16 \times 15 = 120j$
Step2: Calculate left-hand side
$240 = 120j$
Step3: Isolate $j$ (divide by 120)
$j = \frac{240}{120}$
Step4: Solve for $x$ (add 8 to both sides)
$90 + 8 = 10x$
Step5: Calculate left-hand side
$98 = 10x$
Step6: Isolate $x$ (divide by 10)
$x = \frac{98}{10}$
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$j = 2$, $x = 9.8$