Question

$$\frac{3! + 0!}{2! cdot 1!} =$$
\\(\frac{7}{2}\\)
\\(3\\)
\\(\frac{3}{2}\\)

Explanation:

Step1: Calculate factorial values

Recall that $n! = n\times(n-1)\times\cdots\times1$, and $0! = 1$.
$3! = 3\times2\times1 = 6$, $0! = 1$, $2! = 2\times1 = 2$, $1! = 1$

Step2: Substitute into numerator/denominator

Numerator: $3! + 0! = 6 + 1 = 7$
Denominator: $2! \cdot 1! = 2 \times 1 = 2$

Step3: Compute final fraction

$\frac{\text{Numerator}}{\text{Denominator}} = \frac{7}{2}$

Answer:

7/2