Question

$\frac{x^{2}-12x+20}{x-2}$

Explanation:

Step1: Factor the numerator

We need two numbers that multiply to $20$ and add to $-12$. These numbers are $-10$ and $-2$.
$x^2 - 12x + 20 = (x - 10)(x - 2)$

Step2: Cancel common factors

Since $x
eq 2$ (to avoid division by zero), we can cancel $(x - 2)$ from numerator and denominator.
$\frac{(x - 10)(x - 2)}{x - 2} = x - 10$

Answer:

$x - 10$ (where $x
eq 2$)