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Question
$overrightarrow{qs}$ bisects $angle pqr$ and $mangle pqs = 63^{circ}$.
Step1: Recall angle - bisector property
An angle - bisector divides an angle into two equal parts. So if $\overrightarrow{QS}$ bisects $\angle PQR$, then $\angle PQS=\angle SQR$.
Step2: Find the measure of $\angle PQR$
Since $\angle PQR=\angle PQS + \angle SQR$ and $\angle PQS=\angle SQR = 63^{\circ}$, then $\angle PQR=63^{\circ}+63^{\circ}$.
$\angle PQR = 126^{\circ}$
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$126^{\circ}$