Question

simplify. $\frac{49u^{2}v^{3}}{7u^{3}v^{4}}$

Explanation:

Step1: Simplify coefficient

$\frac{49}{7}=7$

Step2: Simplify $u$ - terms using exponent rule $\frac{a^m}{a^n}=a^{m - n}$

$\frac{u^{2}}{u^{3}}=u^{2-3}=u^{-1}=\frac{1}{u}$

Step3: Simplify $v$ - terms using exponent rule $\frac{a^m}{a^n}=a^{m - n}$

$\frac{v^{3}}{v^{4}}=v^{3 - 4}=v^{-1}=\frac{1}{v}$

Step4: Combine results

$7\times\frac{1}{u}\times\frac{1}{v}=\frac{7}{uv}$

Answer:

$\frac{7}{uv}$