Question

simplify
$sqrt{46}$
$sqrt{72}$
$sqrt{116}$
$sqrt{99}$

Explanation:

Step1: Simplify $\sqrt{16}$

$16 = 4^2$, so $\sqrt{16} = \sqrt{4^2} = 4$

Step2: Simplify $\sqrt{72}$

Factor 72 into $36 \times 2$, so $\sqrt{72} = \sqrt{36 \times 2} = \sqrt{6^2 \times 2} = 6\sqrt{2}$

Step3: Simplify $\sqrt{116}$

Factor 116 into $4 \times 29$, so $\sqrt{116} = \sqrt{4 \times 29} = \sqrt{2^2 \times 29} = 2\sqrt{29}$

Step4: Simplify $\sqrt{919}$

919 is a prime number, so $\sqrt{919}$ cannot be simplified further.

Answer:

$\sqrt{16} = 4$
$\sqrt{72} = 6\sqrt{2}$
$\sqrt{116} = 2\sqrt{29}$
$\sqrt{919}$ remains as $\sqrt{919}$