Question

simplify. $sqrt4{6} cdot sqrt4{3}$

Explanation:

Step1: Apply radical product rule

For positive real numbers, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{a \cdot b}$. So:
$\sqrt[4]{6} \cdot \sqrt[4]{3} = \sqrt[4]{6 \times 3}$

Step2: Multiply the radicands

Calculate the product inside the radical:
$\sqrt[4]{6 \times 3} = \sqrt[4]{18}$

Answer:

$\sqrt[4]{18}$