Question

solve for $j$.
$3(-6j - 2) = -13 - 11j - 6j$
$j = \square$

Explanation:

Step1: Expand left-hand side

$3(-6j - 2) = -18j - 6$

Step2: Simplify right-hand side

$-13 - 11j - 6j = -13 - 17j$

Step3: Set sides equal, rearrange terms

$-18j - 6 = -13 - 17j$
$-18j + 17j = -13 + 6$

Step4: Solve for $j$

$-j = -7$
$j = 1$

Answer:

$j = 1$