QUESTION IMAGE
Question
solve for x.
Step1: Set up the equation
Since the two angles $(3x + 10)^{\circ}$ and $(5x - 30)^{\circ}$ are corresponding angles (assuming the lines are parallel, which is a common geometric - setup for such angle - solving problems), they are equal. So we set up the equation $3x+10 = 5x - 30$.
Step2: Move the x - terms to one side
Subtract $3x$ from both sides: $3x+10-3x=5x - 30-3x$, which simplifies to $10 = 2x-30$.
Step3: Move the constant to the other side
Add 30 to both sides: $10 + 30=2x-30 + 30$, resulting in $40 = 2x$.
Step4: Solve for x
Divide both sides by 2: $\frac{40}{2}=\frac{2x}{2}$, so $x = 20$.
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$20$