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solve. $\frac{x+4}{7}-\frac{3}{8}=\frac{9}{8}$

Question

solve.
$\frac{x+4}{7}-\frac{3}{8}=\frac{9}{8}$

Explanation:

Step1: Simplify the constant terms

First, combine the constant fractions on the left side.
$\frac{x+4}{7} - \frac{3}{8} = \frac{9}{8}$
$\frac{x+4}{7} = \frac{9}{8} + \frac{3}{8}$
$\frac{x+4}{7} = \frac{12}{8} = \frac{3}{2}$

Step2: Eliminate the denominator

Multiply both sides by 7 to isolate the numerator with $x$.
$x+4 = \frac{3}{2} \times 7$
$x+4 = \frac{21}{2}$

Step3: Solve for $x$

Subtract 4 from both sides to solve for $x$.
$x = \frac{21}{2} - 4$
$x = \frac{21}{2} - \frac{8}{2}$
$x = \frac{13}{2}$

Answer:

$x = \frac{13}{2}$ or $x=6.5$