Question

tiles
$(ad)^2 + 1^2 = 2^2$
$(ad)^2 = 3$
$a^2 + b^2 = c^2$
$(ad)^2 + 1 = 4$
$ad = \sqrt{3}$

Explanation:

Step1: State Pythagorean theorem

$a^2 + b^2 = c^2$

Step2: Substitute values into theorem

$(AD)^2 + 1^2 = 2^2$

Step3: Simplify squared terms

$(AD)^2 + 1 = 4$

Step4: Isolate $(AD)^2$

$(AD)^2 = 3$

Step5: Solve for $AD$

$AD = \sqrt{3}$

Answer:

1. $a^2 + b^2 = c^2$
2. $(AD)^2 + 1^2 = 2^2$
3. $(AD)^2 + 1 = 4$
4. $(AD)^2 = 3$
5. $AD = \sqrt{3}$