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Question
$(x-1)(x+2)(x+4)$
Step1: Multiply first two binomials
$(x-1)(x+2) = x^2 + 2x - x - 2 = x^2 + x - 2$
Step2: Multiply result by third binomial
$(x^2 + x - 2)(x+4) = x^2(x+4) + x(x+4) - 2(x+4)$
Step3: Expand each term
$= x^3 + 4x^2 + x^2 + 4x - 2x - 8$
Step4: Combine like terms
$= x^3 + (4x^2+x^2) + (4x-2x) - 8 = x^3 + 5x^2 + 2x - 8$
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$x^3 + 5x^2 + 2x - 8$