Question

the measure of minor arc jl is $60^{\circ}$. what is the measure of angle jkl?
$\bigcirc$ $110^{\circ}$
$\bigcirc$ $120^{\circ}$
$\bigcirc$ $130^{\circ}$
$\bigcirc$ $140^{\circ}$

Explanation:

Step1: Identify quadrilateral MJKL

MJ and ML are radii, so $MJ = ML$. JK and LK are tangents, so $\angle MJK = \angle MLK = 90^\circ$.

Step2: Sum quadrilateral interior angles

The sum of interior angles of a quadrilateral is $360^\circ$. Let $\angle JKL = x$.
Expression: $90^\circ + 90^\circ + 60^\circ + x = 360^\circ$

Step3: Solve for x

Simplify the equation:
$240^\circ + x = 360^\circ$
$x = 360^\circ - 240^\circ = 120^\circ$

Answer:

B. 120°