Question

1. in mice, black fur is dominant over white fur, and black eyes are dominant over red eyes. which of the following is possible? two parent mice with black fur have offspring with white fur. two parents with white fur have offspring with black fur. two parents with red eyes have offspring with black eyes. none of the above are possible.

Explanation:

Let's assume the allele for black fur is \(B\) (dominant) and for white fur is \(b\) (recessive), and for black eyes is \(E\) (dominant) and for red eyes is \(e\) (recessive). Two parent mice with black fur can be heterozygous (\(Bb\)). When two \(Bb\) mice mate, using Punnett - square analysis, they can produce offspring with the genotype \(bb\) (white fur). Two white - furred parents (\(bb\)) can only pass on the \(b\) allele and thus cannot have black - furred offspring. Two red - eyed parents (\(ee\)) can only pass on the \(e\) allele and cannot have black - eyed offspring.

Answer:

Two parent mice with black fur have offspring with white fur.