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r = 2 mm volume of sphere = $\frac{4}{3}pi r^{3}$ $piapprox3.14$ what i…

Question

r = 2 mm volume of sphere = $\frac{4}{3}pi r^{3}$ $piapprox3.14$ what is the approximate volume of the marble? a. 16.7 mm³ b. 25.0 mm³ c. 32.0 mm³ d. 33.5 mm³ e. 100.5 mm³

Explanation:

Step1: Substitute the radius value

Given $r = 2$ mm and the volume formula $V=\frac{4}{3}\pi r^{3}$, substitute $r$ into the formula: $V=\frac{4}{3}\times3.14\times2^{3}$.

Step2: Calculate $2^{3}$

$2^{3}=2\times2\times2 = 8$. So the formula becomes $V=\frac{4}{3}\times3.14\times8$.

Step3: Calculate $\frac{4}{3}\times3.14\times8$

$\frac{4}{3}\times3.14\times8=\frac{4\times3.14\times8}{3}=\frac{100.48}{3}\approx33.5$ mm³.

Answer:

D. $33.5$ mm³