Question

ms. jones invested $17,000 in two accounts, one yielding 8% interest and the other yielding 11%. if she received a total of $1,690 in interest at the end of the year, how much did she invest in each account? the amount invested at 8% was $\square.

Explanation:

Step1: Define variables for investments

Let $x$ = amount invested at 8%, so $17000 - x$ = amount invested at 11%.

Step2: Set up interest equation

Total interest = 8% of $x$ + 11% of $(17000-x)$
$$0.08x + 0.11(17000 - x) = 1690$$

Step3: Expand and simplify the equation

$$0.08x + 1870 - 0.11x = 1690$$
$$-0.03x + 1870 = 1690$$

Step4: Isolate the variable term

$$-0.03x = 1690 - 1870$$
$$-0.03x = -180$$

Step5: Solve for $x$

$$x = \frac{-180}{-0.03} = 6000$$

Answer:

6000