Question

multiple-choice question
what should you add to both sides of the equation?
-2
4
2
-4
rewatch

Explanation:

Step1: Analyze the context

Assuming the equation is related to completing the square or isolating a variable, typically when dealing with a term like \(x^2 - 4x\) (for example), to complete the square, we take half of the coefficient of \(x\), square it. But since the question is about what to add to both sides, and the options include 4, -4, 2, -2. If we assume the equation has a term like \(x^2 - 4x\), to complete the square, we add \((\frac{-4}{2})^2 = 4\) to both sides. But wait, maybe the equation is \(x^2 + 2x\) or something else? Wait, the options are -2,4,2,-4. Wait, maybe the equation is \(x^2 - 4x = c\), then we add 4. But maybe the original equation is missing? Wait, the user's question is about what to add to both sides. Wait, maybe the equation is \(x^2 - 4x + \dots\) or maybe a linear equation? Wait, no, the options are numbers. Wait, maybe the equation is \(x^2 - 4x = 0\) and we need to complete the square, so add 4. Or maybe the equation is \(x - 4 = 0\), but no. Wait, maybe the equation is \(x^2 + 2x = 0\), then add 1, but 1 is not an option. Wait, the options are -2,4,2,-4. Wait, maybe the equation is \(x^2 - 4x = 5\), then we add 4 to both sides. So the correct answer is 4? Wait, no, maybe the equation is \(x^2 - 2x = 0\), then add 1, but 1 is not an option. Wait, maybe the equation is \(x - 2 = 0\), but no. Wait, maybe the original problem (not shown) has an equation like \(x^2 - 4x = c\), so we add 4. So the answer is 4. Wait, but let's think again. If the equation is \(x^2 - 4x = 3\), then to complete the square, we take half of -4, which is -2, square it to get 4, so we add 4 to both sides. So the correct option is 4.

Answer:

4 (assuming the equation context where completing the square or balancing requires adding 4, e.g., for \(x^2 - 4x\) terms)