Question

multiply.
$6ab\left(xa^{8}+ya^{8}-7\
ight)$
$6ab\left(xa^{8}+ya^{8}-7\
ight)=\square$

Explanation:

Step1: Distribute \(6ab\) to \(xa^8\)

Using the distributive property \(c(a + b + d)=ca+cb+cd\), we multiply \(6ab\) with \(xa^8\). When multiplying variables with exponents, we add the exponents for the same base (\(a\) here). So \(6ab\times xa^8 = 6x\times a^{1 + 8}\times b=6xa^9b\).

Step2: Distribute \(6ab\) to \(ya^8\)

Similarly, \(6ab\times ya^8=6y\times a^{1 + 8}\times b = 6ya^9b\).

Step3: Distribute \(6ab\) to \(- 7\)

Multiplying \(6ab\) with \(-7\) gives \(6ab\times(-7)=-42ab\).

Step4: Combine the terms

Now we combine the three terms we got from the distribution: \(6xa^9b+6ya^9b - 42ab\).

Answer:

\(6xa^9b + 6ya^9b - 42ab\)