Question

multiply $3(y+2)$.select one:a. $3y+2$b. $9$c. $9y$d. $3y+6$the two legs of a right triangle are 5 and 12, what is the hypotenuse?select one:a. 17b. 13c. 8d. 169

Explanation:

Step1: Apply distributive property

$3(y+2) = 3\times y + 3\times2$

Step2: Calculate each term

$3\times y + 3\times2 = 3y + 6$

Step3: Use Pythagorean theorem

Let $a=5$, $b=12$, hypotenuse $c$. Formula: $c=\sqrt{a^2+b^2}$

Step4: Substitute values and compute

$c=\sqrt{5^2+12^2}=\sqrt{25+144}=\sqrt{169}=13$

Answer:

1. d. 3y+6
2. b. 13