Question

name:area of a trapezoidformula: $a = \frac{1}{2} \times (b_1 + b_2) \times h$find the area of each trapezoid.a.5 m6 m9 marea =b.3 ft4 ft5 ftarea =c.2 m10 m6 marea =d.7 ft4 ft4 ftarea =e.4 m9 m8 marea =f.7 cm10 cm8 cmarea =g.8 in7 in4 inarea =h.2 cm3 cm6 cmarea =i.7 ft6 ft10 ftarea =

Explanation:

Step1: Recall trapezoid area formula

$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Step2: Calculate area for a.

Substitute $b_1=5$, $b_2=9$, $h=6$:
$A = \frac{1}{2} \times (5+9) \times 6 = \frac{1}{2} \times 14 \times 6 = 42$

Step3: Calculate area for b.

Substitute $b_1=3$, $b_2=5$, $h=4$:
$A = \frac{1}{2} \times (3+5) \times 4 = \frac{1}{2} \times 8 \times 4 = 16$

Step4: Calculate area for c.

Substitute $b_1=2$, $b_2=6$, $h=10$:
$A = \frac{1}{2} \times (2+6) \times 10 = \frac{1}{2} \times 8 \times 10 = 40$

Step5: Calculate area for d.

Substitute $b_1=7$, $b_2=4$, $h=4$:
$A = \frac{1}{2} \times (7+4) \times 4 = \frac{1}{2} \times 11 \times 4 = 22$

Step6: Calculate area for e.

Substitute $b_1=4$, $b_2=8$, $h=9$:
$A = \frac{1}{2} \times (4+8) \times 9 = \frac{1}{2} \times 12 \times 9 = 54$

Step7: Calculate area for f.

Substitute $b_1=7$, $b_2=10$, $h=8$:
$A = \frac{1}{2} \times (7+10) \times 8 = \frac{1}{2} \times 17 \times 8 = 68$

Step8: Calculate area for g.

Substitute $b_1=8$, $b_2=4$, $h=7$:
$A = \frac{1}{2} \times (8+4) \times 7 = \frac{1}{2} \times 12 \times 7 = 42$

Step9: Calculate area for h.

Substitute $b_1=2$, $b_2=6$, $h=3$:
$A = \frac{1}{2} \times (2+6) \times 3 = \frac{1}{2} \times 8 \times 3 = 12$

Step10: Calculate area for i.

Substitute $b_1=7$, $b_2=10$, $h=6$:
$A = \frac{1}{2} \times (7+10) \times 6 = \frac{1}{2} \times 17 \times 6 = 51$

Answer:

a. $\boldsymbol{42\ m^2}$
b. $\boldsymbol{16\ ft^2}$
c. $\boldsymbol{40\ m^2}$
d. $\boldsymbol{22\ ft^2}$
e. $\boldsymbol{54\ m^2}$
f. $\boldsymbol{68\ cm^2}$
g. $\boldsymbol{42\ in^2}$
h. $\boldsymbol{12\ cm^2}$
i. $\boldsymbol{51\ ft^2}$