Question

order the expressions from least to greatest. $6^2 - 6$ $4^2 + 2^2$ $5^2$

Explanation:

Step1: Calculate \(6^2 - 6\)

First, calculate the square of 6: \(6^2 = 36\). Then subtract 6: \(36 - 6 = 30\). So \(6^2 - 6 = 30\).

Step2: Calculate \(4^2 + 2^2\)

Calculate the squares: \(4^2 = 16\) and \(2^2 = 4\). Then add them: \(16 + 4 = 20\). So \(4^2 + 2^2 = 20\).

Step3: Calculate \(5^2\)

Calculate the square of 5: \(5^2 = 25\).

Step4: Order the results

Now we have the values: 20 (from \(4^2 + 2^2\)), 25 (from \(5^2\)), and 30 (from \(6^2 - 6\)). Ordering from least to greatest: \(20 < 25 < 30\), so \(4^2 + 2^2 < 5^2 < 6^2 - 6\).

Answer:

\(4^2 + 2^2\), \(5^2\), \(6^2 - 6\) (in order from least to greatest)