Question

in the parking lot below, the spaces are parallel to one another. m∠1=(7y - 3)° and m∠2=(7x + 15)°. determine the values of x and y. x = and y =

Explanation:

Step1: Identify angle - relationship

Since the parking - lot spaces are parallel, $\angle1$ and $\angle2$ are corresponding angles and are equal. So, $7y - 3=7x + 15$. Also, assume $\angle2 = 60^{\circ}$ (from the figure).

Step2: Solve for $x$

Set $7x+15 = 60$. Subtract 15 from both sides: $7x=60 - 15$. So, $7x = 45$, and $x=\frac{45}{7}\approx6.43$.

Step3: Solve for $y$

Since $7y - 3=60$ (because $\angle1=\angle2 = 60^{\circ}$), add 3 to both sides: $7y=60 + 3$. Then $7y = 63$, and $y = 9$.

Answer:

$x=\frac{45}{7}$, $y = 9$