QUESTION IMAGE
Question
part 1: connecting arithmetic sequences and direct variation
a truck driver is beginning her haul across the country. the warehouse is 15 miles from the highway. once she gets on the highway she maintains a constant rate for several hours. complete the table of values for the sequence below that relates hours on the highway and distance from the warehouse is miles.
| hours driven (h) | distance from warehouse (d) |
|---|---|
| 1 | 80 |
| 2 | 145 |
| 3 | |
| 4 | |
| 5 | |
| 6 |
- how much does the truckers distance from the warehouse increase every hour?
- what is the rate of change for the sequence?
- can we figure out the trucks speed from this information? if so, what is it?
- how can we figure out how far away from the warehouse the trucker will be in the next hour?
- if the truck continues traveling at the same rate for 2 more hours, how many more miles will the distance from the warehouse increase?
- what if the trucker continues at the same rate for 3 more hours? 4 more hours?
- in general, if the trucker continues at the same rate for h more hours, how could we calculate how much farther away she will be?
Step1: Find distance increase per hour
Subtract distance at hour 0 from hour 1. $80 - 15=65$ miles.
Step2: Define rate of change
The rate of change is the change in distance per unit - time. Since the distance increases by 65 miles every hour, the rate of change is 65 miles per hour.
Step3: Determine truck's speed
The truck's speed is equal to the rate of change of the distance - time relationship. So the speed is 65 miles per hour.
Step4: Calculate next - hour distance
Add the speed (65 miles per hour) to the current distance. For example, if at hour $n$ the distance is $D_n$, at hour $n + 1$ the distance $D_{n+1}=D_n+65$.
Step5: Calculate distance increase for 2 hours
Multiply the speed by the number of hours. $65\times2 = 130$ miles.
Step6: Calculate distance increase for 3 and 4 hours
For 3 hours: $65\times3=195$ miles. For 4 hours: $65\times4 = 260$ miles.
Step7: General formula for distance increase
Multiply the speed (65 miles per hour) by the number of additional hours $h$. The additional distance $d = 65h$.
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- 65 miles
- 65 miles per hour
- Yes, 65 miles per hour
- Add 65 miles to the current distance from the warehouse.
- 130 miles
- 195 miles for 3 more hours, 260 miles for 4 more hours
- $65h$ miles