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part ii: quadratic relations part a: multiple choice: circle the correc…

Question

part ii: quadratic relations
part a: multiple choice: circle the correct answer. 7 marks

  1. the graph of ( y = x^2 - x - 12 ) will cross the ( y )-axis at

a) 1
b) (-1)
c) (-12)
d) 12

  1. the expanded form of ( (x + 4)(x - 2) ) is

a) ( 2x^2 + 4x - 8 )
b) ( x^2 + 2x - 8 )
c) ( 2x^2 - 8 )
d) ( x^2 - 2x - 8 )

  1. the factored form of ( x^2 - 2x - 15 ) is

a) ( (x + 5)(x - 3) )
b) ( (x - 5)(x + 3) )
c) ( (x - 5)(x + 10) )
d) ( (x - 5)(x - 3) )

  1. when the equation ( (x - 3)(x + 8) = 0 ) is solved, the solutions, also called the zeroes, are

a) (-3) and 8
b) (-24) and 0
c) 5 and 0
d) 3 and (-8)

  1. a parabola with vertex ((-4, 0)) has the equation of the axis of symmetry

a) ( x = 0 )
b) ( y = 0 )
c) ( x = -4 )
d) ( y = -4 )

  1. which of the following statements is false regarding the parabola defined by the relation ( y = x^2 )?

a) it represents a parabola in standard position.
b) the vertex of the parabola lies at the origin.
c) the axis of symmetry is the ( y )-axis.
d) the point ( (2, -4) ) lies on the curve.

  1. what is the factored form of the expression ( -21x^2 + 72 )?

a) ( -3(7x^2 - 24) )
b) ( 3(7x^2 - 24) )
c) ( -3(7x^2 + 24) )
d) ( 3(7x^2 + 24) )

Explanation:

Response
Question 1

Step1: Recall y - axis crossing rule

To find where a graph crosses the y - axis, we set \(x = 0\) in the equation of the function.

Step2: Substitute \(x = 0\) into \(y=x^{2}-x - 12\)

When \(x = 0\), we have \(y=0^{2}-0 - 12=- 12\).

Step1: Use the distributive property (FOIL method)

The formula for \((a + b)(c + d)=ac+ad+bc+bd\). For \((x + 4)(x - 2)\), we have \(a=x\), \(b = 4\), \(c=x\), \(d=-2\).
So, \((x + 4)(x - 2)=x\times x+x\times(-2)+4\times x + 4\times(-2)\)

Step2: Simplify the terms

\(x\times x=x^{2}\), \(x\times(-2)=-2x\), \(4\times x = 4x\), \(4\times(-2)=-8\). Then combine like terms: \(x^{2}-2x + 4x-8=x^{2}+2x - 8\)

Step1: Recall factoring of quadratic \(x^{2}+bx + c=(x + m)(x + n)\) where \(m + n=b\) and \(mn=c\)

For \(x^{2}-2x - 15\), we need two numbers \(m\) and \(n\) such that \(m + n=-2\) and \(mn=-15\). The numbers are \(-5\) and \(3\) since \(-5+3=-2\) and \(-5\times3=-15\).

Step2: Write the factored form

So, \(x^{2}-2x - 15=(x - 5)(x + 3)\) (because \(x-5=x+(-5)\) and \(x + 3\))

Answer:

c) \(-12\)

Question 2