Question

a particular type of cell triples in number every hour. which function can be used to find the number of cells present at the end of h hours if there are initially 6 of these cells?
f(h) = 6(3)^h
f(h) = 3(6)^h
f(h) = 3(6h)
f(h) = 6×h

Explanation:

Step1: Recall exponential growth formula

The general form of exponential growth is $f(t) = a(b)^t$, where $a$ is the initial amount, $b$ is the growth factor, and $t$ is time.

Step2: Identify given values

Initial cells $a=6$, growth factor $b=3$ (triples each hour), time $t=h$.

Step3: Substitute values into formula

Substitute $a=6$, $b=3$, $t=h$ into the growth formula: $f(h) = 6(3)^h$.

Answer:

f(h) = 6(3)^h