QUESTION IMAGE
Question
the perimeter of a rectangle is 48 inches. the length of the rectangle is 3 times the width of the rectangle. what is the area of the rectangle?
hint: perimeter is all four sides added together... and area = length x width
the area is
Step1: Define variables for width/length
Let width = $w$, length = $3w$
Step2: Use perimeter formula to solve for $w$
Perimeter formula: $P = 2(\text{length} + \text{width})$
Substitute values: $48 = 2(3w + w)$
Simplify: $48 = 2(4w) = 8w$
Solve for $w$: $w = \frac{48}{8} = 6$
Step3: Calculate length
Length = $3w = 3 \times 6 = 18$
Step4: Calculate area using formula
Area formula: $A = \text{length} \times \text{width}$
Substitute values: $A = 18 \times 6$
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108 square inches