Question

persevere with problems the bullseye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest hundredth, find the area of the target outside of the bullseye. use 3.14 for π.

Explanation:

Step1: Recall the formula for the area of a circle

The area of a circle is given by \( A = \pi r^2 \), where \( r \) is the radius of the circle.

Step2: Find the area of the entire target

The radius of the entire target is \( 9 \) inches. Using the formula for the area of a circle, we substitute \( r = 9 \) and \( \pi = 3.14 \):
\( A_{\text{entire}} = 3.14 \times 9^2 \)
\( = 3.14 \times 81 \)
\( = 254.34 \) square inches.

Step3: Find the area of the bullseye

The radius of the bullseye is \( 3 \) inches. Using the formula for the area of a circle, we substitute \( r = 3 \) and \( \pi = 3.14 \):
\( A_{\text{bullseye}} = 3.14 \times 3^2 \)
\( = 3.14 \times 9 \)
\( = 28.26 \) square inches.

Step4: Find the area outside the bullseye

To find the area of the target outside the bullseye, we subtract the area of the bullseye from the area of the entire target:
\( A_{\text{outside}} = A_{\text{entire}} - A_{\text{bullseye}} \)
\( = 254.34 - 28.26 \)
\( = 226.08 \) square inches.

Answer:

\( 226.08 \)