Question

is the point (-6, 12) on the circle defined by (x + 10)^2+(y - 2)^2=9?
yes
no

Explanation:

Step1: Substitute x and y values

Substitute \(x = - 6\) and \(y = 12\) into \((x + 10)^2+(y - 2)^2\).
\((-6 + 10)^2+(12 - 2)^2\)

Step2: Calculate the first part

Calculate \((-6 + 10)^2\).
\((-6 + 10)^2=4^2 = 16\)

Step3: Calculate the second part

Calculate \((12 - 2)^2\).
\((12 - 2)^2=10^2 = 100\)

Step4: Calculate the sum

Find the sum of the two results.
\(16+100=116
eq9\)
Since substituting the point \((-6,12)\) into the circle - equation gives a value not equal to 9, the point is not on the circle.

Answer:

B. No