Question

the population of bacteria in an experiment increases by 84% every 2 days. if there were 75 bacteria microorganisms at the beginning, how many would there be after 20 days?
future amount = 75(1 + 0.84)^?
future amount = i(1 + r)^t
enter the number that belongs in the green box

Explanation:

Step1: Determine the number of 2 - day intervals

The time period is 20 days and the growth period is 2 days. So the number of 2 - day intervals $n=\frac{20}{2}=10$.

Step2: Identify the formula components

The initial amount $I = 75$, the growth rate $r=0.84$, and the number of time - periods $t$ (in 2 - day intervals) is what goes in the exponent. Here $t = 10$.

Answer:

10