QUESTION IMAGE
Question
post test: foundations of geometry
drag the tiles to the boxes to form correct pairs. not all tiles will be used.
match the correct figure to each label.
figures with points c, t, m, d and different line/angle representations
labels: \\(\overline{cd}\\), \\(\overrightarrow{cd}\\), \\(\angle ctm\\) with boxes to drag to
Step1: Analyze $\boldsymbol{\overline{CD}}$ (Segment CD)
A segment has two endpoints and is a part of a line with a definite length. The figure with points C and D as endpoints (the one with the segment between C and D, no arrows or only the segment part) matches. Looking at the tiles, the tile with just the segment CD (the one with C and D as endpoints, no arrows extending beyond) is the segment.
Step2: Analyze $\boldsymbol{\overrightarrow{CD}}$ (Ray CD)
A ray has a starting point (C) and extends infinitely in the direction of D. So the figure with an arrow starting at C and going through D (extending beyond D) is the ray. The tile with C as the start and an arrow going through D (like the one with C on the left, D on the right, and an arrow to the right) is the ray.
Step3: Analyze $\boldsymbol{\angle CTM}$ (Angle CTM)
An angle is formed by two rays with a common vertex. The vertex here is T, with rays TC and TM. So the figure with vertex T and two rays from T (TC and TM) is the angle. The tile with T as the vertex, and two rays going out (one towards C, one towards M) is the angle.
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- $\overline{CD}$: The tile with segment CD (C and D as endpoints, no extended arrows).
- $\overrightarrow{CD}$: The tile with ray CD (arrow starting at C, going through D).
- $\angle CTM$: The tile with vertex T and rays TC, TM.
(Note: Based on the figure descriptions, the specific tile positions would be matched as per the visual:
- $\overline{CD}$: The tile with just the segment between C and D (e.g., the one with C and D, no arrows beyond).
- $\overrightarrow{CD}$: The tile with an arrow starting at C, passing through D (extending right).
- $\angle CTM$: The tile with vertex T, and two rays from T (TC and TM).)