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problem 15: (first taught in lesson 24) find x and y. (3x + 20)° (2y - …

Question

problem 15: (first taught in lesson 24) find x and y. (3x + 20)° (2y - 5)° (x + 50)° after you enter your answer press go. x = y =

Explanation:

Step1: Use property of parallel - sided angles

In a parallelogram, consecutive angles are supplementary. So, $(3x + 20)+(x + 50)=180$.
Combining like - terms: $3x+x+20 + 50=180$, which simplifies to $4x+70 = 180$.
Subtract 70 from both sides: $4x=180 - 70=110$.
Divide both sides by 4: $x=\frac{110}{4}=15$.

Step2: Use property of opposite angles

In a parallelogram, opposite angles are equal. So, $2y-5=x + 50$.
Substitute $x = 15$ into the equation: $2y-5=15 + 50$.
$2y-5=65$.
Add 5 to both sides: $2y=65 + 5=70$.
Divide both sides by 2: $y = 35$.

Answer:

$x = 15$, $y = 50$