Question

problem 4
determine the values of a, b, c, and d.
(chart and table content as shown in the image, with expressions like a, a+b, b+5, 3c+d and values related to 60, and a table with variables a, b, c, d and some given values like 16 for a, 10 for b)

Explanation:

Step1: Solve for $a$

Sum of first column equals 60:
$$3a + 12 = 60$$
$$3a = 60 - 12$$
$$3a = 48$$
$$a = \frac{48}{3} = 16$$

Step2: Solve for $b$

Sum of second column equals 60:
$$4(b + 5) = 60$$
$$b + 5 = \frac{60}{4} = 15$$
$$b = 15 - 5 = 10$$

Step3: Solve for $c$

Sum of third column equals 60:
$$(a + b) + c = 60$$
Substitute $a=16, b=10$:
$$(16 + 10) + c = 60$$
$$26 + c = 60$$
$$c = 60 - 26 = 34$$

Step4: Solve for $d$

Sum of fourth column equals 60:
$$3c + d = 60$$
Substitute $c=34$:
$$3(34) + d = 60$$
$$102 + d = 60$$
$$d = 60 - 102 = -42$$

Answer:

Variable	Value
$b$	10
$c$	34
$d$	-42